Skip to content

fix: update Chudnovsky problem source link and informal description #133

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
kim-em merged 1 commit into from
May 6, 2026
+6 −6
Merged

fix: update Chudnovsky problem source link and informal description #133

Show file tree
Hide file tree
Changes from all commits
Commits
Show all changes
1 commit
Select commit
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
6 changes: 3 additions & 3 deletions generated/chudnovsky_formula_for_pi_inv/README.md
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -5,9 +5,9 @@ Chudnovsky formula for pi inverse
- Problem ID: `chudnovsky_formula_for_pi_inv`
- Test Problem: no
- Submitter: Kim Morrison
- Notes: Uses the existing Mathlib definition of the Chudnovsky series and asks for the missing identity with pi inverse.
- Source: https://link.springer.com/article/10.1007/s40316-018-0102-6
- Informal solution: Evaluate the Chudnovsky series and prove that it sums to 1 / pi.
- Notes: Uses the existing Mathlib definition of the Chudnovsky series and asks for the missing identity with pi inverse. The Chudnovsky formula states 1/π = (12 / 640320^(3/2)) · ∑_{n=0}^∞ (-1)^n · (6n)! · (545140134·n + 13591409) / ((3n)! · (n!)^3 · 640320^(3n)).
- Source: https://arxiv.org/abs/1809.00533
- Informal solution: Prove that the Chudnovsky series 1/π = (12 / 640320^(3/2)) · ∑_{n=0}^∞ (-1)^n · (6n)! · (545140134·n + 13591409) / ((3n)! · (n!)^3 · 640320^(3n)) holds, e.g. following Milla's detailed complex-analytic proof.

Do not modify `Challenge.lean` or `Solution.lean`. Those files are part of the
trusted benchmark and fixed by the repository.
Expand Down
6 changes: 3 additions & 3 deletions manifests/problems.toml
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -40,9 +40,9 @@ test = false
module = "LeanEval.Analysis.Chudnovsky"
holes = ["chudnovsky_formula_for_pi_inv"]
submitter = "Kim Morrison"
notes = "Uses the existing Mathlib definition of the Chudnovsky series and asks for the missing identity with pi inverse."
source = "https://link.springer.com/article/10.1007/s40316-018-0102-6"
informal_solution = "Evaluate the Chudnovsky series and prove that it sums to 1 / pi."
notes = "Uses the existing Mathlib definition of the Chudnovsky series and asks for the missing identity with pi inverse. The Chudnovsky formula states 1/π = (12 / 640320^(3/2)) · ∑_{n=0}^∞ (-1)^n · (6n)! · (545140134·n + 13591409) / ((3n)! · (n!)^3 · 640320^(3n))."
source = "https://arxiv.org/abs/1809.00533"
informal_solution = "Prove that the Chudnovsky series 1/π = (12 / 640320^(3/2)) · ∑_{n=0}^∞ (-1)^n · (6n)! · (545140134·n + 13591409) / ((3n)! · (n!)^3 · 640320^(3n)) holds, e.g. following Milla's detailed complex-analytic proof."

[[problem]]
id = "pi1_circle_mulEquiv_int"
Expand Down
Loading