S30 DP-2 Completed

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[super30admin]

Paint House (coinchange2.py)

This submission solves a different problem than what was assigned. The "Paint House" problem requires ensuring no two adjacent houses have the same color, which involves dynamic programming across three color states. Your solution for "Coin Change II" is well-implemented with proper time/space complexity analysis, but it doesn't address the house painting problem at all.

To improve, please ensure you're solving the correct problem as specified. For the Paint House problem, consider using a DP approach where dp[i][j] represents the minimum cost to paint house i with color j, where j can be 0 (red), 1 (blue), or 2 (green), and adjacent houses cannot share the same color.

VERDICT: NEEDS_IMPROVEMENT

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Coin Change II (painthouse.py)

Strengths:

• The code is well-formatted and follows good Python conventions
• The comments accurately describe the complexity for the Paint House problem
• Variable naming is descriptive and consistent

Critical Issues:

1. Wrong Problem: You submitted a solution for "Paint House" but the assignment was "Coin Change II". These are completely different problems requiring different algorithmic approaches.
2. Wrong Function: The problem requires a change(amount, coins) method, but you implemented minCost(costs).
3. No Attempt at Coin Change II: There is no evidence of understanding or attempting the Coin Change II problem.

What You Should Do:
For Coin Change II, you need to:

1. Create a change(amount, coins) method
2. Use dynamic programming to count combinations (not minimum cost)
3. Build a DP table where dp[i] represents the number of ways to make amount i
4. Iterate through coins and update the DP table

The reference solution shows a recursive approach - you could also implement it iteratively with a 1D DP array.

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VERDICT: NEEDS_IMPROVEMENT