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38 changes: 38 additions & 0 deletions LinkedlistcycleII.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,38 @@
'''
Time: O(N)
Space: O(1)
'''

# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None

class Solution:
def isCycle(self,slow,fast):
while fast and fast.next:
slow = slow.next
fast = fast.next.next
if slow == fast:
return [True, fast]
return [False, fast]

def detectCycle(self, head: Optional[ListNode]) -> Optional[ListNode]:
slow = fast = head
cycle = self.isCycle(slow,fast)
fast = cycle[1]
if cycle[0]:
while slow != fast:
slow = slow.next
fast = fast.next
return slow
return None








28 changes: 28 additions & 0 deletions remove_nth_node_from_end_of_list.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,28 @@
'''
Time complexity: O(N)
Space complexity: O(1)
'''
# Definition for singly-linked list.
class ListNode:
def __init__(self, x):
self.val = x
self.next = None

class Solution:
class Solution:
def removeNthFromEnd(self, head: Optional[ListNode], n: int) -> Optional[ListNode]:
dummyNode = ListNode(0,head)
slow = dummyNode
fast = head

while fast and n > 0:
fast = fast.next
n -= 1

while fast:
slow = slow.next
fast = fast.next

slow.next = slow.next.next

return dummyNode.next
45 changes: 45 additions & 0 deletions reverse_linked_list.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,45 @@
'''
Iterrative method:
time complexity: O(N)
space complexity: O(1)

Recursive method:
time complexity: O(N)
space complexity: O(N)
'''
class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
class Solution:
# iterative way
def reverseList(self, head: Optional[ListNode]) -> Optional[ListNode]:
if not head or head.next:
return head
prev = None
curr = head
next = None

while curr:
next = curr.next
prev = curr.next
prev = curr
curr = next
return prev

#recursive way
def reverseList(self, head: Optional[ListNode]) -> Optional[ListNode]:
if not head or not head.next:
return head

new_head = self.reverseList(head.next)
head.next.next = head
head.next = None
return new_head